[numeric.ops.midpoint]

🔗

template<class T>
  constexpr T midpoint(T a, T b) noexcept;

Returns: Half the sum of a and b.

If T is an integer type and the sum is odd, the result is rounded towards a.

Remarks: No overflow occurs.

If T is a floating-point type, at most one inexact operation occurs.

🔗

template<class T>
  constexpr T* midpoint(T* a, T* b);

Preconditions: a and b point to, respectively, elements i and j of the same array object x.

[Note 1:

As specified in [basic.compound], an object that is not an array element is considered to belong to a single-element array for this purpose and a pointer past the last element of an array of n elements is considered to be equivalent to a pointer to a hypothetical array element n for this purpose.

— end note]

Returns: A pointer to array element

i + \frac{j - i 2 of x, where the result of the division is truncated towards zero .}{2}

26 Algorithms library [algorithms]

26.10 Generalized numeric operations [numeric.ops]

26.10.16 Midpoint [numeric.ops.midpoint]