std::chrono::year::operator++, std::chrono::year::operator--
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C++
Date and time library
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std::chrono::year
| Member functions | ||||
year::operator++year::operator-- | ||||
| Nonmember functions | ||||
| Helper classes | ||||
(C++26) |
| constexpr std::chrono::year& operator++() noexcept; |
(1) | (since C++20) |
| constexpr std::chrono::year operator++( int ) noexcept; |
(2) | (since C++20) |
| constexpr std::chrono::year& operator--() noexcept; |
(3) | (since C++20) |
| constexpr std::chrono::year operator--( int ) noexcept; |
(4) | (since C++20) |
Adds or subtracts 1 from the year value.
1,2) Performs *this += std::chrono::years{1};.
3,4) Performs *this -= std::chrono::years{1};.
Contents |
[edit] Parameters
(none)
[edit] Return value
1,3) A reference to this
year after modification.2,4) A copy of the
year made before modification.[edit] Notes
If the result would be outside the range [-32767, 32767], the actual stored value is unspecified.
[edit] Example
Run this code
#include <chrono> #include <iostream> int main() { std::cout << std::boolalpha; std::chrono::year y{2020}; std::cout << (++y == std::chrono::year(2021) << ' '; std::cout << (--y == std::chrono::year(2020) << '\n'; using namespace std::literals::chrono_literals; y = 32767y; y++; /← unspecified, see ↑ Notes ↑ std::cout << static_cast<int>(y) << '\n'; }
Possible output:
true true -32768
[edit] See also
adds or subtracts a number of years from a year (public member function) [edit] | |
| (C++20) |
performs arithmetic on years (function) [edit] |