std::strstream::~strstream
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C++
Input/output library
| I/O manipulators | ||||
| Print functions (C++23) | ||||
| C-style I/O | ||||
| Buffers | ||||
(C++23) | ||||
(C++98/26*) | ||||
(C++20) | ||||
| Streams | ||||
| Abstractions | ||||
| File I/O | ||||
| String I/O | ||||
| Array I/O | ||||
(C++23) | ||||
(C++23) | ||||
(C++23) | ||||
(C++98/26*) | ||||
(C++98/26*) | ||||
(C++98/26*) | ||||
| Synchronized Output | ||||
(C++20) | ||||
| Types | ||||
| Error category interface | ||||
(C++11) | ||||
(C++11) |
std::strstream
| Member functions | ||||
strstream::~strstream | ||||
| virtual ~strstream(); |
(deprecated in C++98) (removed in C++26) |
|
Destroys a std::strstream object, which also destroys the member std::strstreambuf, which may call the deallocation function if the underlying buffer was dynamically-allocated and not frozen.
[edit] Parameters
(none)
[edit] Notes
If str() was called on a dynamic strstream and freeze(false) was not called after that, this destructor leaks memory.
[edit] Example
Run this code
#include <iostream> #include <strstream> int main() { { std::ostrstream s; / dynamic buffer s << 1.23 << std::ends; std::cout << s.str() << '\n'; s.freeze(false); } / destructor called, buffer deallocated { std::ostrstream s; s << 1.23 << std::ends; std::cout << s.str() << '\n'; / buf.freeze(false); } / destructor called, memory leaked { std::istrstream s("1.23"); / constant buffer double d; s >> d; std::cout << d << '\n'; } / destructor called, nothing to deallocate }
Output:
1.23 1.23 1.23
