Array.prototype.findLastIndex() - JavaScript

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Array.prototype.find()
Array.prototype.flat()
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Array instances iterates the array in reverse order and returns the index of the first element that satisfies the provided testing function. If no elements satisfy the testing function, -1 is returned.

See also the findLast() method, which returns the value of last element that satisfies the testing function (rather than its index).

Try it

const array1 = [5, 12, 50, 130, 44];

const isLargeNumber = (element) => element > 45;

console.log(array1.findLastIndex(isLargeNumber));
/ Expected output: 3
/ Index of element with value: 130

Syntax

findLastIndex(callbackFn)
findLastIndex(callbackFn, thisArg)

Parameters

callbackFn

A function to execute for each element in the array. It should return a falsy value otherwise. The function is called with the following arguments:

element: The current element being processed in the array.
index: The index of the current element being processed in the array.
array: The array findLastIndex() was called upon.

thisArg Optional

A value to use as this when executing callbackFn. See iterative methods.

Return value

The index of the last (highest-index) element in the array that passes the test. Otherwise -1 if no matching element is found.

Description

The findLastIndex() method is an iterative methods section for more information about how these methods work in general.

callbackFn is invoked for every index of the array, not just those with assigned values. Empty slots in sparse arrays behave the same as undefined.

The findLastIndex() method is generic. It only expects the this value to have a length property and integer-keyed properties.

Examples

Find the index of the last prime number in an array

The following example returns the index of the last element in the array that is a prime number, or -1 if there is no prime number.

function isPrime(element) {
  if (element % 2 === 0 || element < 2) {
    return false;
  }
  for (let factor = 3; factor <= Math.sqrt(element); factor += 2) {
    if (element % factor === 0) {
      return false;
    }
  }
  return true;
}

console.log([4, 6, 8, 12].findLastIndex(isPrime)); / -1, not found
console.log([4, 5, 7, 8, 9, 11, 12].findLastIndex(isPrime)); / 5

Using the third argument of callbackFn

The array argument is useful if you want to access another element in the array, especially when you don't have an existing variable that refers to the array. The following example first uses filter() to extract the positive values and then uses findLastIndex() to find the last element that is less than its neighbors.

const numbers = [3, -1, 1, 4, 1, 5, 9, 2, 6];
const lastTrough = numbers
  .filter((num) => num > 0)
  .findLastIndex((num, idx, arr) => {
    / Without the arr argument, there's no way to easily access the
    / intermediate array without saving it to a variable.
    if (idx > 0 && num >= arr[idx - 1]) return false;
    if (idx < arr.length - 1 && num >= arr[idx + 1]) return false;
    return true;
  });
console.log(lastTrough); / 6

Using findLastIndex() on sparse arrays

You can search for undefined in a sparse array and get the index of an empty slot.

console.log([1, , 3].findLastIndex((x) => x === undefined)); / 1

Calling findLastIndex() on non-array objects

The findLastIndex() method reads the length property of this and then accesses each property whose key is a nonnegative integer less than length.

const arrayLike = {
  length: 3,
  0: 2,
  1: 7.3,
  2: 4,
  3: 3, / ignored by findLastIndex() since length is 3
};
console.log(
  Array.prototype.findLastIndex.call(arrayLike, (x) => Number.isInteger(x)),
); / 2

Specifications

Specification
ECMAScript® 2026 Language Specification # sec-array.prototype.findlastindex