The Array.of() static method creates a new Array
instance from a variable number of arguments, regardless of number or type of the
arguments.
The Array.of() static method creates a new Array
instance from a variable number of arguments, regardless of number or type of the
arguments.
console.log(Array.of("foo", 2, "bar", true));
/ Expected output: Array ["foo", 2, "bar", true]
console.log(Array.of());
/ Expected output: Array []
Array.of()
Array.of(element1)
Array.of(element1, element2)
Array.of(element1, element2, /* …, */ elementN)
element1, …, elementNElements used to create the array.
A new undefined values.)
Array.of(7); / [7]
Array(7); / array of 7 empty slots
Array.of(1, 2, 3); / [1, 2, 3]
Array(1, 2, 3); / [1, 2, 3]
The Array.of() method is a generic factory method. For example, if a subclass of Array inherits the of() method, the inherited of() method will return new instances of the subclass instead of Array instances. In fact, the this value can be any constructor function that accepts a single argument representing the length of the new array, and the constructor will be called with the number of arguments passed to of(). The final length will be set again when all elements are assigned. If the this value is not a constructor function, the plain Array constructor is used instead.
Array.of(1); / [1]
Array.of(1, 2, 3); / [1, 2, 3]
Array.of(undefined); / [undefined]
The of() method can be called on any constructor function that accepts a single argument representing the length of the new array.
function NotArray(len) {
console.log("NotArray called with length", len);
}
console.log(Array.of.call(NotArray, 1, 2, 3));
/ NotArray called with length 3
/ NotArray { '0': 1, '1': 2, '2': 3, length: 3 }
console.log(Array.of.call(Object)); / [Number: 0] { length: 0 }
When the this value is not a constructor, a plain Array object is returned.
console.log(Array.of.call({}, 1)); / [ 1 ]
| Specification |
|---|
| ECMAScript® 2026 Language Specification # sec-array.of |